Home Maths JEE - Advanced Previous Year Paper JEE-Advanced-2021-Paper-2 SECTION 2 • This section contains THREE (03)…
Maths JEE - Advanced Previous Year Paper JEE-Advanced-2021-Paper-2 Numeric Response
Published on: August 13, 2026

SECTION 2

• This section contains THREE (03) question stems.

• There are TWO (02) questions corresponding to each question stem.

• The answer to each question is a NUMERICAL VALUE.

• For each question, enter the correct numerical value corresponding to the answer in the designated place using the mouse and the on-screen virtual numeric keypad.

• If the numerical value has more than two decimal places, truncate/round-off the value to TWO decimal places.

• Answer to each question will be evaluated according to the following marking scheme:

Full Mark : +2 If ONLY the correct numerical value is entered at the designated place;

Zero Marks : 0 In all other cases.

Question Stem for Question Nos. 7 and 8

Question Stem

At 298 K, the limiting molar conductivity of a weak monobasic acid is 4 x 10 2 S cm 2 mol -1 . At 298 K, for an aqueous solution of the acid the degree of dissociation is a and the molar conductivity is yx10 2 S cm 2 mol -1 . At 298 K, upon 20 times dilution with water, the molar conductivity of the solution becomes 3yxl0 2 S cm 2 mor 1

(i) The value of is_______.

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Text Solution

Verified by Experts
The correct answer is:
0.22

(0.22)

On dilution conductivity increases three times

Since temperature is constant K a will be constant

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